The resonance in a series RLC circuit occurs when the inductive reactance equals the capacitive reactance. The formula for the resonant frequency is given by:

f = 1 / (2π√(LC))

where:
L = inductance = 125 mH = 125 x 10^-3 H
C = capacitance = 60 μF = 60 x 10^-6 F

Substituting these values into the formula, we get:

f = 1 / (2π√((125 x 10^-3) * (60 x 10^-6)))
f = 1 / (2π√(7.5 x 10^-6))
f = 1 / (2π * 0.0027386128)
f = 1 / 0.0172
f = 58.14 Hz

So, the resonant frequency is approximately 58.14 Hz.

Now, to find the current at the resonant frequency, we use Ohm's law (I = V/R), where V is the voltage and R is the resistance. Substituting the given values, we get:

I = V / R
I = 120 V / 10 Ω
I = 12 A

So, the current flowing at the resonant frequency is 12 A.

Question

The resonance in a series RLC circuit occurs when the inductive reactance equals the capacitive reactance. The formula for the resonant frequency is given by:

f = 1 / (2π√(LC))

where:
L = inductance = 125 mH = 125 x 10^-3 H
C = capacitance = 60 μF = 60 x 10^-6 F

Substituting these values into the formula, we get:

f = 1 / (2π√((125 x 10^-3) * (60 x 10^-6)))
f = 1 / (2π√(7.5 x 10^-6))
f = 1 / (2π * 0.0027386128)
f = 1 / 0.0172
f = 58.14 Hz

So, the resonant frequency is approximately 58.14 Hz.

Now, to find the current at the resonant frequency, we use Ohm's law (I = V/R), where V is the voltage and R is the resistance. Substituting the given values, we get:

I = V / R
I = 120 V / 10 Ω
I = 12 A

So, the current flowing at the resonant frequency is 12 A.

Knowee AI · Accepted Answer

The resonance in a series RLC circuit occurs when the inductive reactance equals the capacitive reactance. The formula for the resonant frequency is given by:

f = 1 / (2π√(LC))

where:
L = inductance = 125 mH = 125 x 10^-3 H
C = capacitance = 60 μF = 60 x 10^-6 F

Substituting these values into the formula, we get:

f = 1 / (2π√((125 x 10^-3) * (60 x 10^-6)))
f = 1 / (2π√(7.5 x 10^-6))
f = 1 / (2π * 0.0027386128)
f = 1 / 0.0172
f = 58.14 Hz

So, the resonant frequency is approximately 58.14 Hz.

Now, to find the current at the resonant frequency, we use Ohm's law (I = V/R), where V is the voltage and R is the resistance. Substituting the given values, we get:

I = V / R
I = 120 V / 10 Ω
I = 12 A

So, the current flowing at the resonant frequency is 12 A.

A coil having a resistance of 10 Ω and an inductance of 125 mH is connected in series with a 60μF capacitor across a 120 V supply. At what frequency does resonance occurs? Find the currentflowing at the resonant frequency.

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