What will be the output of the following pseudocode?Integer p, q, r Set p = 0, q = 4, r = 3 If(p || r) If(p && r) p = p &r End If p = p ^ r End If Print p + q + r
Question
What will be the output of the following pseudocode?Integer p, q, r Set p = 0, q = 4, r = 3 If(p || r) If(p && r) p = p &r End If p = p ^ r End If Print p + q + r
Solution
The pseudocode provided is a mix of logical and bitwise operations. Here's a step-by-step breakdown:
- Initialize p = 0, q = 4, r = 3.
- The first if condition checks if either p or r is not zero. Since r is 3, the condition is true, so we enter the if block.
- The next if condition checks if both p and r are not zero. Since p is 0, the condition is false, so we skip the inner if block.
- Then, we perform a bitwise XOR operation between p and r. Since p is 0, the result is simply r, which is 3. So, p becomes 3.
- Finally, we print the sum of p, q, and r, which is 3 + 4 + 3 = 10.
So, the output of the pseudocode will be 10.
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