The problem is asking to find the maximum amount of money Chef can earn in N hours. Chef has two types of sessions: Type 1 session, which lasts 1 hour, and earns Chef X rupees and Type 2 session, which lasts 2 hours, and earns Chef Y rupees (YX).

Here are the steps to solve this problem:

1. First, we need to understand that Chef should always prefer to conduct a Type 2 session if possible because it earns him more money (YX). However, he can only conduct a Type 2 session if he has at least 2 hours available.

2. For each test case, we first check if N is even or odd. If N is even, Chef can conduct N/2 Type 2 sessions. If N is odd, Chef can conduct (N-1)/2 Type 2 sessions and 1 Type 1 session.

3. We then calculate the total money Chef can earn by multiplying the number of each type of session with their respective prices.

4. However, there is a special case where conducting Type 1 sessions for all available hours can earn Chef more money. This happens when 2*X Y. In this case, Chef should conduct Type 1 sessions for all N hours.

5. Finally, we compare the money Chef can earn in the special case with the money he can earn in the normal case and return the maximum of the two.

Here is a Python code snippet that implements the above steps:

```python
T = int(input())
for _ in range(T):
N, X, Y = map(int, input().split())
if 2*X Y:
print(N*X)
else:
if N % 2 == 0:
print(N//2*Y)
else:
print(N//2*Y + X)
```

This code reads the number of test cases T and for each test case, it reads N, X, and Y. It then checks if 2*X Y and if so, it prints N*X. Otherwise, it checks if N is even or odd and prints the maximum money Chef can earn accordingly.

Question

The problem is asking to find the maximum amount of money Chef can earn in N hours. Chef has two types of sessions: Type 1 session, which lasts 1 hour, and earns Chef X rupees and Type 2 session, which lasts 2 hours, and earns Chef Y rupees (Y>X).

Here are the steps to solve this problem:

1. First, we need to understand that Chef should always prefer to conduct a Type 2 session if possible because it earns him more money (Y>X). However, he can only conduct a Type 2 session if he has at least 2 hours available.

2. For each test case, we first check if N is even or odd. If N is even, Chef can conduct N/2 Type 2 sessions. If N is odd, Chef can conduct (N-1)/2 Type 2 sessions and 1 Type 1 session.

3. We then calculate the total money Chef can earn by multiplying the number of each type of session with their respective prices.

4. However, there is a special case where conducting Type 1 sessions for all available hours can earn Chef more money. This happens when 2*X > Y. In this case, Chef should conduct Type 1 sessions for all N hours.

5. Finally, we compare the money Chef can earn in the special case with the money he can earn in the normal case and return the maximum of the two.

Here is a Python code snippet that implements the above steps:

```python
T = int(input())
for _ in range(T):
    N, X, Y = map(int, input().split())
    if 2*X > Y:
        print(N*X)
    else:
        if N % 2 == 0:
            print(N//2*Y)
        else:
            print(N//2*Y + X)
```

This code reads the number of test cases T and for each test case, it reads N, X, and Y. It then checks if 2*X > Y and if so, it prints N*X. Otherwise, it checks if N is even or odd and prints the maximum money Chef can earn accordingly.

Knowee AI · Accepted Answer