Savings AccountConsidering the new budget, Chef decided to keep all his money in a savings account.Chef has 𝑋X income sources where he gets 𝑌Y rupees from each source. However, due to bank restrictions, Chef can keep at most 𝑍Z rupees in the savings account.Find the minimum number of income sources Chef should reduce to maximise his savings without exceeding the account's limit.Input FormatThe first line of input will contain a single integer 𝑇T, denoting the number of test cases.Each test case consists of three space-separated integers 𝑋,𝑌,X,Y, and 𝑍Z — the number of income sources, amount received from each source and the maximum limit of savings account respectively.Output FormatFor each test case, output on a new line, the minimum number of income sources Chef should reduce to maximise his savings without exceeding the account's limit.Constraints1≤𝑇≤1041≤T≤10 4 1≤𝑋,𝑌≤101≤X,Y≤101≤𝑍≤1001≤Z≤100Sample 1:InputOutput31 2 42 4 63 10 12012Explanation:Test case 11: Chef can store a maximum of 44 rupees in his bank account. He has 11 income source from where he gets 22 rupees. Since the total income is not more than the limit of account, he does not need to decrease any income source.Test case 22: Chef can store a maximum of 66 rupees in his bank account. He has 22 income sources from where he gets 44 rupees each. Currently the total income is more than the limit of account.Chef will reduce one income source so that his total income becomes 44 rupees which lies within the limit of account.
Question
Savings AccountConsidering the new budget, Chef decided to keep all his money in a savings account.Chef has 𝑋X income sources where he gets 𝑌Y rupees from each source. However, due to bank restrictions, Chef can keep at most 𝑍Z rupees in the savings account.Find the minimum number of income sources Chef should reduce to maximise his savings without exceeding the account's limit.Input FormatThe first line of input will contain a single integer 𝑇T, denoting the number of test cases.Each test case consists of three space-separated integers 𝑋,𝑌,X,Y, and 𝑍Z — the number of income sources, amount received from each source and the maximum limit of savings account respectively.Output FormatFor each test case, output on a new line, the minimum number of income sources Chef should reduce to maximise his savings without exceeding the account's limit.Constraints1≤𝑇≤1041≤T≤10 4 1≤𝑋,𝑌≤101≤X,Y≤101≤𝑍≤1001≤Z≤100Sample 1:InputOutput31 2 42 4 63 10 12012Explanation:Test case 11: Chef can store a maximum of 44 rupees in his bank account. He has 11 income source from where he gets 22 rupees. Since the total income is not more than the limit of account, he does not need to decrease any income source.Test case 22: Chef can store a maximum of 66 rupees in his bank account. He has 22 income sources from where he gets 44 rupees each. Currently the total income is more than the limit of account.Chef will reduce one income source so that his total income becomes 44 rupees which lies within the limit of account.
Solution
To solve this problem, we need to calculate the total income Chef is currently receiving from all his income sources and compare it with the maximum limit of the savings account.
Here are the steps to solve this problem:
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Calculate the total income Chef is currently receiving. This can be done by multiplying the number of income sources (X) with the amount received from each source (Y). Let's denote this as total_income = X * Y.
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Compare total_income with the maximum limit of the savings account (Z).
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If total_income is less than or equal to Z, Chef does not need to reduce any income sources. So, the output will be 0.
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If total_income is more than Z, Chef needs to reduce some income sources. The number of income sources to be reduced can be calculated as follows:
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First, calculate the difference between total_income and Z. Let's denote this as diff = total_income - Z.
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The number of income sources to be reduced is the smallest integer greater than or equal to diff/Y. This can be calculated using the ceiling division of diff by Y. In Python, this can be done as (diff + Y - 1) // Y.
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So, the output will be the number of income sources to be reduced.
This solution works because by reducing the income sources that give the highest amount, Chef can maximize his savings without exceeding the account's limit.
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