If a wire having modulus of elasticity is 2 x 1011N/m2 is stretched to 2cm when we apply a force 10N, what is the elastic potential energy of wire?
Question
If a wire having modulus of elasticity is 2 x 1011N/m2 is stretched to 2cm when we apply a force 10N, what is the elastic potential energy of wire?
Solution
To calculate the elastic potential energy of the wire, we can use the formula for the elastic potential energy stored in a stretched wire, which is given by:
U = 1/2 * F * Δx
where: U is the elastic potential energy, F is the force applied, and Δx is the extension of the wire.
Given in the problem, F = 10N and Δx = 2cm = 0.02m.
Substituting these values into the formula, we get:
U = 1/2 * 10N * 0.02m = 0.1 Joules
So, the elastic potential energy of the wire is 0.1 Joules.
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