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Mona was married five years ago. Today her age is 6/5times her age at the time of her marriage. At present, her daughter's age is 1/10th of her age. What was her daughter's age two years ago?

Question

Mona was married five years ago. Today her age is 6/5times her age at the time of her marriage. At present, her daughter's age is 1/10th of her age. What was her daughter's age two years ago?

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Solution

Let's break down the problem step by step:

  1. Let's assume Mona's age at the time of her marriage was 'x' years.

  2. According to the problem, Mona's current age is 6/5 times her age at the time of her marriage. So, we can write this as: 6/5*x.

  3. The problem also states that Mona's daughter's current age is 1/10th of Mona's age. So, her daughter's age is: 1/10 * (6/5x) = 6/50x = 3/25*x.

  4. We're asked to find out the daughter's age two years ago. Since we know her current age, we simply subtract 2 from it: (3/25*x) - 2.

  5. But we also know that Mona was married 5 years ago, and her current age is 6/5 times her age at the time of her marriage. This means that 6/5*x = x + 5. Solving this equation gives us x = 25.

  6. Substituting x = 25 in the equation from step 4 gives us the daughter's age two years ago: (3/25*25) - 2 = 3 - 2 = 1.

So, Mona's daughter was 1 year old two years ago.

This problem has been solved

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