What is the mole fraction in instantaneous distillate if:Moles of liquid in residue at start W0= 1000Moles of liquid in residue at end W= 300Mole fraction in liquid at start X0 = 0.6Mole fraction in liquid at end X= 0.5
Question
What is the mole fraction in instantaneous distillate if:Moles of liquid in residue at start W0= 1000Moles of liquid in residue at end W= 300Mole fraction in liquid at start X0 = 0.6Mole fraction in liquid at end X= 0.5
Solution
To calculate the mole fraction in the instantaneous distillate, we can use the material balance for the component in the distillation process. The total amount of the component in the feed is equal to the total amount of the component in the distillate and the residue.
The total moles of the component in the feed (F) is given by:
F = W0*X0
The total moles of the component in the residue (R) is given by:
R = W*X
The total moles of the component in the distillate (D) is then:
D = F - R
The mole fraction in the distillate (Y) is then:
Y = D / (W0 - W)
Let's calculate:
- Calculate F:
F = W0X0 = 10000.6 = 600 moles
- Calculate R:
R = WX = 3000.5 = 150 moles
- Calculate D:
D = F - R = 600 - 150 = 450 moles
- Calculate Y:
Y = D / (W0 - W) = 450 / (1000 - 300) = 450 / 700 = 0.642857
So, the mole fraction in the instantaneous distillate is approximately 0.643.
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