Knowee
Questions
Features
Study Tools

What output will the following Python script produce?def function2(param):    print (param, param)def function1(part1, part2):    cat = part1 + part2    function2(cat)chant1 = "See Me "chant2 = "See You "function1(chant1, chant2)Question 12Select one:a.See Me See Youb.See You See Me See You See Mec.See Me See You See Me See Youd.None it would generate an error

Question

What output will the following Python script produce?def function2(param):    print (param, param)def function1(part1, part2):    cat = part1 + part2    function2(cat)chant1 = "See Me "chant2 = "See You "function1(chant1, chant2)Question 12Select one:a.See Me See Youb.See You See Me See You See Mec.See Me See You See Me See Youd.None it would generate an error

🧐 Not the exact question you are looking for?Go ask a question

Solution

The output of the given Python script will be:

See Me See You

Explanation:

  1. The script defines a function called "function2" that takes a parameter "param" and prints it twice.
  2. The script also defines a function called "function1" that takes two parameters "part1" and "part2".
  3. Inside "function1", a variable "cat" is created by concatenating "part1" and "part2".
  4. The "function2" is then called with the "cat" variable as the argument.
  5. The "function2" prints the value of "cat" twice, resulting in "See Me See You" being printed as the output.

Therefore, the correct answer is:

a. See Me See You

This problem has been solved

Similar Questions

def function2(param):    print (param, param)    print (cat)def function1(part1, part2):    cat = part1 + part2    function2(cat)chant1 = "See You "chant2 = "See Me"function1(chant1, chant2)Question 5Select one:a.The variable cat is local to function1 and cannot be used in function2b.The variable param is used twice in function2 and this is illegalc.Function2 does not have a return value definedd.Function1 does not have a return value defined

The following Python script will generate an error when executed.  What is the cause of the error?def function2(param):    print (param, param)    print (cat)def function1(part1, part2):    cat = part1 + part2    function2(cat)chant1 = "See You "chant2 = "See Me"function1(chant1, chant2)Question 8Select one:a.The variable cat is local to function1 and cannot be used in function2b.The variable param is used twice in function2 and this is illegalc.Function2 does not have a return value definedd.Function1 does not have a return value defined

What do these lines print?>>> def my_function():>>> print("In my function")>>> >>> my_function“In my function”In my functionfunction my_function at …Nothing

What would be the output of the following Python statement?def func(i):  print('Hello world', i)

What will be the output of the following Python code?class Demo: def __init__(self): self.a = 1 self.__b = 1  def display(self): return self.__b obj = Demo()print(obj.__b)

1/2

Upgrade your grade with Knowee

Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.