The following Python script will generate an error when executed. What is the cause of the error?def function2(param): print (param, param) print (cat)def function1(part1, part2): cat = part1 + part2 function2(cat)chant1 = "See You "chant2 = "See Me"function1(chant1, chant2)Question 8Select one:a.The variable cat is local to function1 and cannot be used in function2b.The variable param is used twice in function2 and this is illegalc.Function2 does not have a return value definedd.Function1 does not have a return value defined
Question
The following Python script will generate an error when executed. What is the cause of the error?def function2(param): print (param, param) print (cat)def function1(part1, part2): cat = part1 + part2 function2(cat)chant1 = "See You "chant2 = "See Me"function1(chant1, chant2)Question 8Select one:a.The variable cat is local to function1 and cannot be used in function2b.The variable param is used twice in function2 and this is illegalc.Function2 does not have a return value definedd.Function1 does not have a return value defined
Solution
The correct answer is a. The variable cat is local to function1 and cannot be used in function2.
In Python, variables that are defined inside a function are local to that function and cannot be accessed from outside that function or by other functions. In this script, the variable 'cat' is defined in function1 and then an attempt is made to use it in function2. This will generate an error because 'cat' is not defined in the scope of function2.
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def function2(param): print (param, param) print (cat)def function1(part1, part2): cat = part1 + part2 function2(cat)chant1 = "See You "chant2 = "See Me"function1(chant1, chant2)Question 5Select one:a.The variable cat is local to function1 and cannot be used in function2b.The variable param is used twice in function2 and this is illegalc.Function2 does not have a return value definedd.Function1 does not have a return value defined
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