The tangential speed (v) of a point rotating in a circle is given by the formula v = rω, where r is the radius of the circle and ω is the angular velocity.

In this case, the length of the cutting cord (0.20 m) is the radius of the circle, and the motor rotates at a rate of 20 revolutions per second.

First, we need to convert the angular velocity from revolutions per second to radians per second, since the standard unit of angular velocity in this formula is rad/s.

1 revolution is equal to 2π radians, so 20 revolutions is equal to 20 * 2π = 40π rad/s.

Now we can substitute r = 0.20 m and ω = 40π rad/s into the formula:

v = rω = 0.20 m * 40π rad/s = 8π m/s ≈ 25 m/s.

So, the tangential speed of the end of the cord is approximately 25 m/s. The correct answer is c. 25 m/s.

Question

The tangential speed (v) of a point rotating in a circle is given by the formula v = rω, where r is the radius of the circle and ω is the angular velocity.

In this case, the length of the cutting cord (0.20 m) is the radius of the circle, and the motor rotates at a rate of 20 revolutions per second.

First, we need to convert the angular velocity from revolutions per second to radians per second, since the standard unit of angular velocity in this formula is rad/s.

1 revolution is equal to 2π radians, so 20 revolutions is equal to 20 * 2π = 40π rad/s.

Now we can substitute r = 0.20 m and ω = 40π rad/s into the formula:

v = rω = 0.20 m * 40π rad/s = 8π m/s ≈ 25 m/s.

So, the tangential speed of the end of the cord is approximately 25 m/s. The correct answer is c. 25 m/s.

Knowee AI · Accepted Answer

The tangential speed (v) of a point rotating in a circle is given by the formula v = rω, where r is the radius of the circle and ω is the angular velocity.

In this case, the length of the cutting cord (0.20 m) is the radius of the circle, and the motor rotates at a rate of 20 revolutions per second.

First, we need to convert the angular velocity from revolutions per second to radians per second, since the standard unit of angular velocity in this formula is rad/s.

1 revolution is equal to 2π radians, so 20 revolutions is equal to 20 * 2π = 40π rad/s.

Now we can substitute r = 0.20 m and ω = 40π rad/s into the formula:

v = rω = 0.20 m * 40π rad/s = 8π m/s ≈ 25 m/s.

So, the tangential speed of the end of the cord is approximately 25 m/s. The correct answer is c. 25 m/s.

The cutting cord on a gas-powered weed cutter is 0.20 m in length. If the motor rotates at the rate of 20 rev/s, what is the tangential speed of the end of the cord?Select one:a.19 m/sb.63 m/sc.25 m/sd.628 m/s

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