A 4.40 μC charge is subject to a 6.00 mN force due to an electric field. What is the magnitude of the electric field at the location of the charge?

What is the magnitude and direction of the electric field due to a -5.8 μC point charge at a distance of 9.8 m?*1 point5.326 kN/C towards the charge0.544 kN/C towards the charge5.686 kN/C away from the charge0.533 kN/C away from the charge

Consider a point 0.5 mm above the midpoint of the two charges. As you can verify by removing one of the positive charges, the electric field due to only one of the positive charges is about 18 V/mV/m . What is the magnitude of the total electric field due to both charges at this location?

The electric field at a point due to a point charge is 30 N/C and the electric potential at that point is 15 J/C respectively. What is the distance of the point from the charge and the magnitude of the charge?0.1 m, 0.43 nC0.4 m, 0.77 nC0.5 m, 0.83 nC0.6 m, 0.31 nC

As clothing tumble in a dryer, they can become charged. If a small piece of lint with a charge of +2.15 E−19 C is attracted to the clothing by a force of 4.0 E−9 N, what is the magnitude of the electric field at this location? 1.9 E10 N/C 5.4 E10 N/C 6.1 E10 N/C 8.6 E10 N/C

A charged particle of charge 4μC is moving perpendicular to a magnetic field with velocity 3 m/s. if it experiences a magnetic force of 3×10−3𝑁 3×10 −3 N , determine the magnitude of the magnetic field.