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Let G be a complete undirected graph on 4 vertices, having 6 edges with weights being 3, 4, 5, 6, 7and 8. The maximum possible total weight that a minimum weight spanning tree of G can have is __.

Question

Let G be a complete undirected graph on 4 vertices, having 6 edges with weights being 3, 4, 5, 6, 7and 8. The maximum possible total weight that a minimum weight spanning tree of G can have is __.

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Solution

To find the maximum possible total weight that a minimum weight spanning tree of G can have, we need to consider the properties of a minimum weight spanning tree.

A minimum weight spanning tree is a tree that connects all vertices of a graph with the minimum total weight possible. In a complete undirected graph on 4 vertices, there are a total of 6 edges connecting the vertices.

To find the minimum weight spanning tree, we can use a greedy algorithm such as Kruskal's algorithm or Prim's algorithm. Both algorithms aim to select edges with the minimum weight while ensuring that the resulting tree remains connected.

In this case, we have 6 edges with weights 3, 4, 5, 6, 7, and 8. To find the maximum possible total weight, we need to select the edges with the highest weights.

By selecting the edges with weights 7 and 8, we can ensure that the total weight of the minimum weight spanning tree is maximized. Therefore, the maximum possible total weight that a minimum weight spanning tree of G can have is 7 + 8 = 15.

This problem has been solved

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