The compound with the higher melting point between CH3CCH2CHO and CH3CCH2CH2OH is CH3CCH2CH2OH.

Here's why:

1. Both compounds have similar molecular weights, so we need to look at the types of intermolecular forces present in each compound to determine which one has a higher melting point.

2. CH3CCH2CHO (propanal) has dipole-dipole interactions due to the presence of a polar carbonyl group (C=O).

3. CH3CCH2CH2OH (1-propanol) has hydrogen bonding due to the presence of an -OH group.

4. Hydrogen bonding is a stronger intermolecular force than dipole-dipole interactions.

5. Therefore, more energy (i.e., a higher temperature) is needed to break the hydrogen bonds in 1-propanol than the dipole-dipole interactions in propanal.

So, CH3CCH2CH2OH (1-propanol) has a higher melting point than CH3CCH2CHO (propanal).

Question

The compound with the higher melting point between CH3CCH2CHO and CH3CCH2CH2OH is CH3CCH2CH2OH.

Here's why:

1. Both compounds have similar molecular weights, so we need to look at the types of intermolecular forces present in each compound to determine which one has a higher melting point.

2. CH3CCH2CHO (propanal) has dipole-dipole interactions due to the presence of a polar carbonyl group (C=O).

3. CH3CCH2CH2OH (1-propanol) has hydrogen bonding due to the presence of an -OH group.

4. Hydrogen bonding is a stronger intermolecular force than dipole-dipole interactions.

5. Therefore, more energy (i.e., a higher temperature) is needed to break the hydrogen bonds in 1-propanol than the dipole-dipole interactions in propanal.

So, CH3CCH2CH2OH (1-propanol) has a higher melting point than CH3CCH2CHO (propanal).

Knowee AI · Accepted Answer

The compound with the higher melting point between CH3CCH2CHO and CH3CCH2CH2OH is CH3CCH2CH2OH.

Here's why:

1. Both compounds have similar molecular weights, so we need to look at the types of intermolecular forces present in each compound to determine which one has a higher melting point.

2. CH3CCH2CHO (propanal) has dipole-dipole interactions due to the presence of a polar carbonyl group (C=O).

3. CH3CCH2CH2OH (1-propanol) has hydrogen bonding due to the presence of an -OH group.

4. Hydrogen bonding is a stronger intermolecular force than dipole-dipole interactions.

5. Therefore, more energy (i.e., a higher temperature) is needed to break the hydrogen bonds in 1-propanol than the dipole-dipole interactions in propanal.

So, CH3CCH2CH2OH (1-propanol) has a higher melting point than CH3CCH2CHO (propanal).

Which compound has the higher melting point? CH33CCH2CHO CH33CCH2CH2OH

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