The intensity of electric field at a point between the plates of a charged capacitorIs directly proportional to the distance between the platesIs inversely proportional to the distance between the platesIs inversely proportional to the square of the distance between the platesDoes not depend upon the distance between the plates

A parallel plate capacitor is charged by a battery of potential V and then disconnected. Now the distance between the plates of capacitor is doubled then the electric field between the plates of capacitor will beChoose answer: Doubled Halved Quadrupled Remain same

A parallel plate capacitor of capacitance C with plates at separation d, has charge Q. The electric field at a distance r from positive plate between the plates isChoose answer:

For a parallel plate capacitor, the capacitance 𝐶C is directly proportional to:a) The area of the platesb) The distance between the platesc) The square of the distance between the platesd) The volume between the plates

If I double the distance between the two plates of a parallel plate capacitor while holding the voltage constant, what happens to the strength of the electric field? Question 3Select one:a.It is reduced to half it's original valueb.It doublesc.It is reduced but not by one half.d.There is not enough information to say.

The energy density in the electric field of a parallel plate capacitor with charge 𝑄Q and capacitance 𝐶C is given by:a) 𝑄22𝐶2CQ 2 ​ b) 𝑄2𝐶CQ 2 ​ c) 𝑄24𝐶4CQ 2 ​ d) 𝑄28𝐶8CQ 2 ​