A parallel plate capacitor of capacitance C with plates at separation d, has charge Q. The electric field at a distance r from positive plate between the plates isChoose answer:
Question
A parallel plate capacitor of capacitance C with plates at separation d, has charge Q. The electric field at a distance r from positive plate between the plates isChoose answer:
Solution
The electric field E in a parallel plate capacitor is given by the equation E = Q/(ε0*A), where Q is the charge, ε0 is the permittivity of free space, and A is the area of one of the plates.
However, in this question, we are not given the area of the plates. Instead, we are given the capacitance C of the capacitor. We can use the relationship between capacitance, area, and plate separation to find the area. The capacitance of a parallel plate capacitor is given by C = ε0A/d. Solving for A, we get A = Cd/ε0.
Substituting this into the equation for the electric field, we get E = Q/(ε0*(Cd/ε0)) = Q/(Cd).
Therefore, the electric field at a distance r from the positive plate between the plates is independent of r and is given by E = Q/(C*d).
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