A barefoot field-goal kicker imparts a speed of 25 m/s to a football at rest. If the football has a mass of 0.50 kg and time of contact with the football is 0.020 s, what is the force exerted on the foot?Select one:a.25 Nb.1,250 Nc.625 Nd.625 Ne.13 N
Question
A barefoot field-goal kicker imparts a speed of 25 m/s to a football at rest. If the football has a mass of 0.50 kg and time of contact with the football is 0.020 s, what is the force exerted on the foot?Select one:a.25 Nb.1,250 Nc.625 Nd.625 Ne.13 N
Solution
To solve this problem, we need to use the formula for force, which is:
F = m*a
Where: F is the force, m is the mass, and a is the acceleration.
We know the mass (m) is 0.50 kg, but we don't know the acceleration (a) yet. We can find the acceleration using the formula:
a = Δv/Δt
Where: Δv is the change in velocity, and Δt is the change in time.
The change in velocity (Δv) is the final velocity minus the initial velocity. In this case, the final velocity is 25 m/s and the initial velocity is 0 m/s (because the football was at rest), so Δv = 25 m/s - 0 m/s = 25 m/s.
The change in time (Δt) is 0.020 s.
So, the acceleration (a) is:
a = Δv/Δt = 25 m/s / 0.020 s = 1250 m/s²
Now we can find the force (F):
F = m*a = 0.50 kg * 1250 m/s² = 625 N
So, the force exerted on the foot is 625 N. Therefore, the correct answer is c. 625 N.
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