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11.An element X has atomic number 30 while element Y has atomic number 8(a) Write the electron arrangementforX (1mark).............................................................................................................................................................................................................................................................................(b) What type of bond would be formed when X andYreact

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11.An element X has atomic number 30 while element Y has atomic number 8(a) Write the electron arrangementforX (1mark).............................................................................................................................................................................................................................................................................(b) What type of bond would be formed when X andYreact

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Solution

(a) The atomic number of an element represents the number of protons in its nucleus, and in a neutral atom, it also represents the number of electrons. So, element X with atomic number 30 has 30 electrons. The electron arrangement for X (Zinc) would be 2, 8, 18, 2. This is based on the energy levels (shells) that can hold a certain number of electrons: the first can hold up to 2, the second can hold up to 8, the third can hold up to 18, and the fourth can hold up to 2 (for the first 30 elements).

(b) Element Y with atomic number 8 is Oxygen, which has 6 electrons in its outer shell and needs 2 more to complete its octet (8 electrons in the outer shell). Element X (Zinc) has 2 electrons in its outer shell. When X and Y react, X would donate its 2 outer electrons to Y. This transfer of electrons from X to Y leads to the formation of an ionic bond.

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