A wheel 20cm starts from rest and rotates about horizontal axis through the center with a constant acceleration of 0.5 radian/sec2. A point from the circumference is directly at the right of the center of the wheel. After the end of 2 seconds, find its resultant.A. 22 cm/sec2B. 22.4 cm/sec2C. 23 cm/sec2D. 25 cm/sec2
Question
A wheel 20cm starts from rest and rotates about horizontal axis through the center with a constant acceleration of 0.5 radian/sec2. A point from the circumference is directly at the right of the center of the wheel. After the end of 2 seconds, find its resultant.A. 22 cm/sec2B. 22.4 cm/sec2C. 23 cm/sec2D. 25 cm/sec2
Solution
To solve this problem, we need to find the tangential and radial (centripetal) accelerations and then combine them to find the resultant acceleration.
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First, let's find the tangential acceleration (at). Tangential acceleration is given by the formula at = r*α, where r is the radius of the wheel and α is the angular acceleration. Substituting the given values, we get at = 0.1m * 0.5 rad/sec^2 = 0.05 m/sec^2.
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Next, let's find the radial or centripetal acceleration (ar). Centripetal acceleration is given by the formula ar = rω^2, where ω is the angular velocity. But we don't have ω directly, we have to find it using the formula ω = ω0 + αt, where ω0 is the initial angular velocity (which is 0 as the wheel starts from rest), α is the angular acceleration and t is the time. Substituting the given values, we get ω = 0 + 0.5 rad/sec^2 * 2 sec = 1 rad/sec. Now, substituting ω in the formula for ar, we get ar = 0.1m * (1 rad/sec)^2 = 0.1 m/sec^2.
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Now, we have both tangential and radial accelerations. The resultant acceleration (a) is given by the formula a = sqrt(at^2 + ar^2). Substituting the values, we get a = sqrt((0.05 m/sec^2)^2 + (0.1 m/sec^2)^2) = sqrt(0.0025 + 0.01) m/sec^2 = sqrt(0.0125) m/sec^2 = 0.1118 m/sec^2.
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Convert this to cm/sec^2 by multiplying by 100, we get a = 11.18 cm/sec^2.
None of the options match the calculated value. There might be a mistake in the question or the options provided.
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