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A ball is projected vertically up with a velocity of 20 m/s. Its velocity when it reaches 15 m height is ______ m/s. (Take g = 10 m/s2)

Question

A ball is projected vertically up with a velocity of 20 m/s. Its velocity when it reaches 15 m height is ______ m/s. (Take g = 10 m/s2)

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Solution

To solve this problem, we can use the equation of motion:

v² = u² - 2gh

where: v is the final velocity (which we're trying to find), u is the initial velocity (20 m/s in this case), g is the acceleration due to gravity (10 m/s²), and h is the height (15 m in this case).

Substituting the given values into the equation, we get:

v² = 20² - 21015 v² = 400 - 300 v² = 100

Taking the square root of both sides to solve for v, we get:

v = √100 v = 10 m/s

So, the velocity of the ball when it reaches a height of 15 m is 10 m/s.

This problem has been solved

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