s we all know, no one comes on time for a class scheduled at 8:30 AM. Fed up with this, theinstructor decided that there is a uniform probability that the doors will be closed sometimebetween 8:30 AM and 8:45 AM. If students always come to class late and as a poisssonprocess with rate λ, what is the expected number of people who will get attendance?
Question
s we all know, no one comes on time for a class scheduled at 8:30 AM. Fed up with this, theinstructor decided that there is a uniform probability that the doors will be closed sometimebetween 8:30 AM and 8:45 AM. If students always come to class late and as a poisssonprocess with rate λ, what is the expected number of people who will get attendance?
Solution
The problem can be solved by using the properties of the Poisson process and the uniform distribution.
Step 1: Define the variables Let's denote T as the time the doors are closed, which is uniformly distributed between 8:30 AM and 8:45 AM, so T ~ U(0,15). Let's denote N as the number of students who arrive before the doors are closed, which follows a Poisson process with rate λ.
Step 2: Calculate the expected number of students who arrive before the doors are closed The expected number of students who arrive before the doors are closed is E[N] = λT. However, since T is a random variable, we need to take its expectation into account.
Step 3: Calculate the expected value of T The expected value of a uniform distribution is (a+b)/2. In this case, a=0 and b=15, so E[T] = (0+15)/2 = 7.5 minutes.
Step 4: Substitute E[T] into the equation for E[N] E[N] = λE[T] = λ*7.5.
So, the expected number of students who will get attendance is λ*7.5.
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