If a number 774958A96B is divisible by 8 and 9, the respectively values of A and B will beOptions5 and 88 and 0None7 and 8

For a number to be divisible by 8, the last three digits must form a number that is divisible by 8. Therefore, we need to find a value for B such that 96B is divisible by 8. The only possible value from the options given is 8, making 968 divisible by 8.

For a number to be divisible by 9, the sum of its digits must be divisible by 9. Therefore, we need to find a value for A such that 7+7+4+9+5+8+A+9+6+8 is divisible by 9. The sum of the known digits is 63, which is already divisible by 9. Therefore, A must be 0 to maintain this divisibility.

So, the values of A and B are 0 and 8 respectively.