Predict the products formed at anode and cathode when the following molten compounds are electrolyzed.Sodium fluorideCopper (II) iodideZinc bromide
Question
Predict the products formed at anode and cathode when the following molten compounds are electrolyzed.Sodium fluorideCopper (II) iodideZinc bromide
Solution
To predict the products formed at the anode and cathode when the following molten compounds are electrolyzed, we need to consider the ions present in each compound.
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Sodium fluoride (NaF): At the anode (positive electrode): The negative fluoride ions (F-) will be attracted to the anode and undergo oxidation. Fluoride ions will lose electrons and form fluorine gas (F2). At the cathode (negative electrode): The positive sodium ions (Na+) will be attracted to the cathode and undergo reduction. Sodium ions will gain electrons and form sodium metal (Na).
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Copper (II) iodide (CuI2): At the anode: The negative iodide ions (I-) will be attracted to the anode and undergo oxidation. Iodide ions will lose electrons and form iodine gas (I2). At the cathode: The positive copper ions (Cu2+) will be attracted to the cathode and undergo reduction. Copper ions will gain electrons and form copper metal (Cu).
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Zinc bromide (ZnBr2): At the anode: The negative bromide ions (Br-) will be attracted to the anode and undergo oxidation. Bromide ions will lose electrons and form bromine gas (Br2). At the cathode: The positive zinc ions (Zn2+) will be attracted to the cathode and undergo reduction. Zinc ions will gain electrons and form zinc metal (Zn).
In summary:
- Sodium fluoride (NaF) will produce fluorine gas (F2) at the anode and sodium metal (Na) at the cathode.
- Copper (II) iodide (CuI2) will produce iodine gas (I2) at the anode and copper metal (Cu) at the cathode.
- Zinc bromide (ZnBr2) will produce bromine gas (Br2) at the anode and zinc metal (Zn) at the cathode.
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