To solve this problem, we need to use the principle of conservation of energy. This principle states that the total energy in a closed system remains constant. In this case, the total energy of the ball remains constant as it falls from the shelf to the floor.

Step 1: Calculate the potential energy (PE) of the ball on the shelf. The formula for potential energy is PE = mgh, where m is mass, g is the acceleration due to gravity, and h is height.

PE = (5.00 kg) * (9.80 m/s^2) * (2.00 m) = 98.0 J

Step 2: As the ball falls, its potential energy is converted into kinetic energy (KE). Just before the ball hits the floor, all its potential energy has been converted into kinetic energy. Therefore, the kinetic energy of the ball just before it hits the floor is equal to the potential energy it had on the shelf.

KE = 98.0 J

So, the correct answer is c. 98.0 J.

Question

To solve this problem, we need to use the principle of conservation of energy. This principle states that the total energy in a closed system remains constant. In this case, the total energy of the ball remains constant as it falls from the shelf to the floor.

Step 1: Calculate the potential energy (PE) of the ball on the shelf. The formula for potential energy is PE = mgh, where m is mass, g is the acceleration due to gravity, and h is height.

PE = (5.00 kg) * (9.80 m/s^2) * (2.00 m) = 98.0 J

Step 2: As the ball falls, its potential energy is converted into kinetic energy (KE). Just before the ball hits the floor, all its potential energy has been converted into kinetic energy. Therefore, the kinetic energy of the ball just before it hits the floor is equal to the potential energy it had on the shelf.

KE = 98.0 J

So, the correct answer is c. 98.0 J.

Knowee AI · Accepted Answer

To solve this problem, we need to use the principle of conservation of energy. This principle states that the total energy in a closed system remains constant. In this case, the total energy of the ball remains constant as it falls from the shelf to the floor.

Step 1: Calculate the potential energy (PE) of the ball on the shelf. The formula for potential energy is PE = mgh, where m is mass, g is the acceleration due to gravity, and h is height.

PE = (5.00 kg) * (9.80 m/s^2) * (2.00 m) = 98.0 J

Step 2: As the ball falls, its potential energy is converted into kinetic energy (KE). Just before the ball hits the floor, all its potential energy has been converted into kinetic energy. Therefore, the kinetic energy of the ball just before it hits the floor is equal to the potential energy it had on the shelf.

KE = 98.0 J

So, the correct answer is c. 98.0 J.

A 5.00 kg ball falls from a 2.00 m-high shelf. Just before hitting the floor, what will be its kinetic energy? (g = 9.80 m/s2 and assume air resistance is negligible)Select one:a.19.6 Jb.49.0 Jc.98.0 Jd.10.0 J

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