Here is a simple solution in C++: ```cpp #include using namespace std; int CheckDivision(int n, int a, int b) { if(n % a == 0 && n % b == 0) return 1; else return 0; } int main() { int n, a, b; cin >> n >> a >> b; if(CheckDivision(n, a, b) == 1) cout << "Divisible by both divisors"; else cout << "Not divisible by both divisors"; return 0; } ``` This program works as follows: 1. The `CheckDivision` function takes three integers as input: `n`, `a`, and `b`. It checks if `n` is divisible by both `a` and `b` by using the modulus operator (`%`). If `n` is divisible by both `a` and `b`, the function returns `1`; otherwise, it returns `0`. 2. In the `main` function, we take three integers as input from the user: `n`, `a`, and `b`. We then call the `CheckDivision` function with these three integers. 3. If the `CheckDivision` function returns `1`, we print "Divisible by both divisors". If it returns `0`, we print "Not divisible by both divisors".

Problem StatementManish is tasked with a problem to check whether a given integer n is divisible by two divisors (a and b) or not. He is supposed to solve this using a call-by-value function. As he is unaware of that concept, he seeks your help.Help him create a function that will return 1 if the integer is divisible by both divisors; otherwise, it will return 0. Print the messages accordingly.Function Specifications: int CheckDivision(int n, int a, int b)Input format :The first line of input consists of an integer n, representing the number for which the divisibility needs to be checked.The second line consists of an integer a, representing the first divisor.The third line consists of an integer b, representing the second divisor.Output format :The output prints one of the following messages indicating whether the number is divisible by both a and b."Divisible by both divisors" if n is divisible by both a and b."Not divisible by both divisors" if n is not divisible by both a and b.Refer to the sample output for formatting specifications.Code constraints :In this scenario, the test cases fall under the following constraints:3 ≤ n ≤ 10001 ≤ a, b ≤ nSample test cases :Input 1 :100010005Output 1 :Divisible by both divisorsInput 2 :312Output 2 :Not divisible by both diviso

Question

Problem StatementManish is tasked with a problem to check whether a given integer n is divisible by two divisors (a and b) or not. He is supposed to solve this using a call-by-value function. As he is unaware of that concept, he seeks your help.Help him create a function that will return 1 if the integer is divisible by both divisors; otherwise, it will return 0. Print the messages accordingly.Function Specifications: int CheckDivision(int n, int a, int b)Input format :The first line of input consists of an integer n, representing the number for which the divisibility needs to be checked.The second line consists of an integer a, representing the first divisor.The third line consists of an integer b, representing the second divisor.Output format :The output prints one of the following messages indicating whether the number is divisible by both a and b."Divisible by both divisors" if n is divisible by both a and b."Not divisible by both divisors" if n is not divisible by both a and b.Refer to the sample output for formatting specifications.Code constraints :In this scenario, the test cases fall under the following constraints:3 ≤ n ≤ 10001 ≤ a, b ≤ nSample test cases :Input 1 :100010005Output 1 :Divisible by both divisorsInput 2 :312Output 2 :Not divisible by both diviso

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Solution 1

Here is a simple solution in C++:

#include<iostream>
using namespace std;

int CheckDivision(int n, int a, int b) {
    if(n % a == 0 && n % b == 0)
        return 1;
    else
        return 0;
}

int main() {
    int n, a, b;
    cin >> n >> a >> b;
    if(CheckDivision(n, a, b) == 1)
        cout << "Divisible by both divisors";
    else
        cout << "Not divisible by both divisors";
    return 0;
}

This program works as follows:

The CheckDivision function takes three integers as input: n, a, and b. It checks if n is divisible by both a and b by using the modulus operator (%). If n is divisible by both a and b, the function returns 1; otherwise, it returns 0.
In the main function, we take three integers as input from the user: n, a, and b. We then call the CheckDivision function with these three integers.
If the CheckDivision function returns 1, we print "Divisible by both divisors". If it returns 0, we print "Not divisible by both divisors".

This problem has been solved

Solution 2

Here is a simple solution in C++:

#include<iostream>
using namespace std;

int CheckDivision(int n, int a, int b) {
    if(n % a == 0 && n % b == 0)
        return 1;
    else
        return 0;
}

int main() {
    int n, a, b;
    cin >> n >> a >> b;
    if(CheckDivision(n, a, b) == 1)
        cout << "Div

Similar Questions

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