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.99 x 10^9 N * m^2/C^2) * (|q|)^2 / (0.25 m)^2

Question

.99 x 10^9 N * m^2/C^2) * (|q|)^2 / (0.25 m)^2

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Solution

Sure, let's break this down:

  1. First, let's simplify the constants: .99 x 10^9 N * m^2/C^2 is the constant for Coulomb's Law, which describes the force between two charges.

  2. (|q|)^2 is the square of the magnitude of the charge. We don't know the exact value of |q|, so we'll leave it as is for now.

  3. (0.25 m)^2 is the square of the distance between the charges. Squaring 0.25 m gives us 0.0625 m^2.

  4. Now, we can plug these values into the equation for Coulomb's Law: F = k * |q1q2| / r^2. In this case, we're assuming that the two charges are the same, so |q1q2| simplifies to (|q|)^2.

  5. Substituting the values in, we get: F = (.99 x 10^9 N * m^2/C^2) * (|q|)^2 / 0.0625 m^2.

  6. We can't simplify this any further without knowing the value of |q|. So, the final answer is F = (.99 x 10^9 N * m^2/C^2) * (|q|)^2 / 0.0625 m^2.

This problem has been solved

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