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What is the molar concentration of a solution of NaOH that has a m/v% of 27.2%?

Question

What is the molar concentration of a solution of NaOH that has a m/v% of 27.2%?

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Solution

To calculate the molar concentration of a solution, we need to know the molarity formula which is:

Molarity (M) = moles of solute / liters of solution

Given that the mass/volume percent (m/v%) is 27.2%, this means that there are 27.2 g of NaOH in 100 mL of solution.

First, we need to convert the mass of NaOH to moles. The molar mass of NaOH is approximately 40 g/mol. So,

Moles of NaOH = 27.2 g / 40 g/mol = 0.68 moles

Next, we need to convert the volume of the solution to liters.

Volume of solution = 100 mL = 0.1 L

Now we can calculate the molarity:

Molarity (M) = 0.68 moles / 0.1 L = 6.8 M

So, the molar concentration of the NaOH solution is 6.8 M.

This problem has been solved

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