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B starts 4.5 minutes after A from the same point, for a place at a distance of 3.5 miles from the starting point. A on reaching the destination turns back and walk a mile where he meets B. If A’s speed is a mile in 6 minutes then B’s speed is a mile in _minutes?Options₹ 9₹ 10₹ 8₹ 12

Question

B starts 4.5 minutes after A from the same point, for a place at a distance of 3.5 miles from the starting point. A on reaching the destination turns back and walk a mile where he meets B. If A’s speed is a mile in 6 minutes then B’s speed is a mile in _minutes?Options₹ 9₹ 10₹ 8₹ 12

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Solution

To solve this problem, we need to first determine how long it took for A to reach the destination and then walk a mile back.

  1. A's speed is 1 mile in 6 minutes. So, to cover a distance of 3.5 miles, A would take 3.5 miles * 6 minutes/mile = 21 minutes.

  2. A then walks a mile back, which would take an additional 6 minutes. So, in total, A has been walking for 21 minutes + 6 minutes = 27 minutes.

  3. However, B started 4.5 minutes after A. So, by the time A and B meet, B has been walking for 27 minutes - 4.5 minutes = 22.5 minutes.

  4. In this time, B has covered a distance of 2.5 miles (3.5 miles - 1 mile that A walked back).

  5. Therefore, B's speed is 2.5 miles / 22.5 minutes = 0.111 miles/minute.

  6. To find out how long it takes for B to walk a mile, we take the reciprocal of this: 1 / 0.111 = 9 minutes.

So, B's speed is a mile in 9 minutes. The correct option is ₹ 9.

This problem has been solved

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