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If the roots of x2 – px + 2 = 0 are equal, then the value of p is:

Question

If the roots of x2 – px + 2 = 0 are equal, then the value of p is:

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Solution

For a quadratic equation ax² + bx + c = 0, the roots are equal when the discriminant (b² - 4ac) is equal to zero.

In the given equation x² - px + 2 = 0, a = 1, b = -p, and c = 2.

So, we set the discriminant equal to zero:

(-p)² - 412 = 0 p² - 8 = 0 p² = 8 p = ± √8 p = ± 2√2

So, the value of p for which the roots of the equation are equal is ± 2√2.

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