If the roots of x2 – px + 2 = 0 are equal, then the value of p is:
Question
If the roots of x2 – px + 2 = 0 are equal, then the value of p is:
Solution
For a quadratic equation ax² + bx + c = 0, the roots are equal when the discriminant (b² - 4ac) is equal to zero.
In the given equation x² - px + 2 = 0, a = 1, b = -p, and c = 2.
So, we set the discriminant equal to zero:
(-p)² - 412 = 0 p² - 8 = 0 p² = 8 p = ± √8 p = ± 2√2
So, the value of p for which the roots of the equation are equal is ± 2√2.
Similar Questions
If one root of the equation 2x2 – 30x + p = 0 is 4 times the other, then find the value of p.
If p and q are the roots of the equation 2x2 − x − 4 = 0. Find p3 + q3
If –4 is a root of the equation x² + px – 4 = 0 and the quadratic equation x² + px + k = 0 has equal roots, find the value of k.
The solution of the equation – 4 = 2 (p – 2) is
Find the value of p so that the quadratic equation px(x – 3) + 9 = 0 has two equal roots
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.