A constant force of 5.60 N acts on a 3.10 kg object for 10.0 s. What are the changes in the object's momentum and velocity?
Question
A constant force of 5.60 N acts on a 3.10 kg object for 10.0 s. What are the changes in the object's momentum and velocity?
Solution
The change in an object's momentum can be calculated using the formula:
Δp = F * Δt
where: Δp is the change in momentum, F is the force, and Δt is the time.
Substituting the given values:
Δp = 5.60 N * 10.0 s = 56.0 kg*m/s
So, the change in the object's momentum is 56.0 kg*m/s.
The change in velocity can be calculated using the formula:
Δv = Δp / m
where: Δv is the change in velocity, m is the mass of the object.
Substituting the given values:
Δv = 56.0 kg*m/s / 3.10 kg = 18.06 m/s
So, the change in the object's velocity is 18.06 m/s.
Similar Questions
The momentum of an object of mass 50 kg is 5,000 kg m/s. What is its velocity?
If an object of mass 10 kg is moving at a constant speed of 5 m/s, what is the net force on the object?Select one:a.0 Nb.50 Nc.10 Nd.100 N
A body of mass 10 kg is moving with velocity-1of 10 ms . A force acts for 5 seconds to reduce-1its velocity to 2 ms . Find the momentum ofbody before and after application of the forceon it
An object of mass 20 kg is moving with a velocity 200 m s-1. If a force is applied so that the momentum is decreased by 100 kg m s-1, determine the new velocity of the object.
an object of mass 40 kg moves with an acceleration of 8 m/s2. the rate of change of momentum in si unit is a.
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.