Determine the oxidation number of Carbon atom in K4[Fe(CN)6]
Question
Determine the oxidation number of Carbon atom in K4[Fe(CN)6]
Solution
The oxidation number of Carbon in K4[Fe(CN)6] is 0.
Step 1: In the complex ion [Fe(CN)6]4-, the oxidation number of Fe is +2.
Step 2: The oxidation number of N in CN- is -3. Since the overall charge of CN- is -1, the oxidation number of C must be +2 to balance the -3 of N.
Step 3: However, in the complex ion [Fe(CN)6]4-, the six CN- ions contribute a charge of -6. To balance this, the oxidation number of Fe is +2 and the oxidation number of C must be 0.
Therefore, the oxidation number of Carbon in K4[Fe(CN)6] is 0.
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