What is wrong with the following code?int n = 0;int array[5];int i = 3;array[n] = i;It is not possible to access array[n]The array array is not entirely initializedIt is impossible to declare the variable array this wayNothing is wrong

What is wrong with the following code?int n = 0;int array[5];int i = 3;array[n] = i;

Analyze the following code and choose the correct answer.int[] arr = new int[5];arr = new int[6];The code has compile errors because the variable arr cannot be changed once it is assigned. The code has runtime errors because the variable arr cannot be changed once it is assigned.The code can compile and run fine. The second line assigns a new array to arr.The code has compile errors because we cannot assign a different size array to arr.

Which of the following is not a correct way to initialize an array?a.int n[ 5 ] = { 0, 7, 0, 3, 8, 2 };b.int n[] = { 0, 7, 0, 3, 8, 2 };c.int n[ 5 ] = { 7 };d.int n[ 5 ] = { 9, 1, 9 };

How is an array initialized in C language?int (a)=[1,2,3];int a[3]={1,2,3};int a[]=new int[3]int a={1,2,3};

Analyze the following code.public class Test {   public static void main(String[] args) {     int[] x = new int[3];     System.out.println("x[0] is " + x[0]);   } } Group of answer choicesThe program has a compile error because the size of the array wasn't specified when declaring the array.The program has a runtime error because the array elements are not initialized.The program runs fine and displays x[0] is 0.The program has a runtime error because the array element x[0] is not defined