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If the following probability distribution is valid, what is P(X=4)? k 1 2 3 4P(X=k) 0.07 0.07  0.04   Please give your answer to 2 decimal places.

Question

If the following probability distribution is valid, what is P(X=4)? k 1 2 3 4P(X=k) 0.07 0.07  0.04   Please give your answer to 2 decimal places.

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Solution

The sum of all probabilities in a probability distribution must equal 1.

Given the probabilities P(X=1) = 0.07, P(X=2) = 0.07, and P(X=3) = 0.04, we can add these together to get 0.18.

Since the total probability must be 1, we subtract this sum from 1 to find the missing probability P(X=4).

So, P(X=4) = 1 - 0.18 = 0.82.

Therefore, the probability P(X=4) is 0.82 or 82% when rounded to two decimal places.

This problem has been solved

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