SLHLDifficulty: Multiple choice questionWhich of the following samples of elements contains the smallest number of atoms?1 g of Br21 g of S81 g of H21 g of O2

To answer this question, we need to calculate the number of atoms in each sample. We can do this by dividing the mass of the sample by the molar mass of the element to get the number of moles, and then multiplying by Avogadro's number (6.022 x 10^23 atoms/mole) to get the number of atoms.

1. For Br2, the molar mass is approximately 160 g/mole. So, 1 g of Br2 is 1/160 = 0.00625 moles. Multiplying by Avogadro's number, we get 0.00625 x 6.022 x 10^23 = 3.76 x 10^22 atoms.

2. For S8, the molar mass is approximately 256 g/mole. So, 1 g of S8 is 1/256 = 0.00391 moles. Multiplying by Avogadro's number, we get 0.00391 x 6.022 x 10^23 = 2.35 x 10^22 atoms.

3. For H2, the molar mass is approximately 2 g/mole. So, 1 g of H2 is 1/2 = 0.5 moles. Multiplying by Avogadro's number, we get 0.5 x 6.022 x 10^23 = 3.01 x 10^23 atoms.

4. For O2, the molar mass is approximately 32 g/mole. So, 1 g of O2 is 1/32 = 0.03125 moles. Multiplying by Avogadro's number, we get 0.03125 x 6.022 x 10^23 = 1.88 x 10^22 atoms.

So, the sample with the smallest number of atoms is 1 g of S8.