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What is the output of the following function calldef outer_fun(a, b):    def inner_fun(c, d):        return c + d     return inner_fun(a, b)    return a result = outer_fun(5, 10)print(result)515(15, 5)Syntax Error

Question

What is the output of the following function calldef outer_fun(a, b):    def inner_fun(c, d):        return c + d     return inner_fun(a, b)    return a result = outer_fun(5, 10)print(result)515(15, 5)Syntax Error

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Solution

The output of the function call will be 15.

Here's the step by step explanation:

  1. The function outer_fun is defined with two parameters a and b.
  2. Inside outer_fun, another function inner_fun is defined with two parameters c and d.
  3. inner_fun returns the sum of c and d.
  4. outer_fun returns the result of calling inner_fun with a and b as arguments.
  5. When outer_fun is called with 5 and 10 as arguments, inner_fun is called with 5 and 10.
  6. inner_fun returns the sum of 5 and 10, which is 15.
  7. This result is then returned by outer_fun, so result is 15.
  8. When result is printed, it outputs 15.

This problem has been solved

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What does the following code do? def outer(x): def inner(y): return x * y return inner f = outer(5) print(f(2)) print(f(3)) print(outer(4)(2)) 10, 15, 810, 15, 2010, 15, 8, 810, 15, 20, 8

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What is the output of the following code snippet?def apply_func(L, func):    return [func(x) for x in L]apply_func([7.1, 17.9], lambda x: x**3)

If you assign the result a void function to a variable in Python, you get:

1/3

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