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Find the Fourier Cosine Transform of๐‘“(๐‘ฅ) = ๐‘ฅ ๐‘’โˆ’5๐‘ฅ.

Question

Find the Fourier Cosine Transform of๐‘“(๐‘ฅ) = ๐‘ฅ ๐‘’โˆ’5๐‘ฅ.

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Solution

To find the Fourier Cosine Transform of ๐‘“(๐‘ฅ) = ๐‘ฅ ๐‘’โˆ’5๐‘ฅ, we can follow these steps:

Step 1: Determine the interval of integration. Since we are dealing with the Fourier Cosine Transform, the interval of integration is from 0 to infinity.

Step 2: Write the Fourier Cosine Transform integral. The Fourier Cosine Transform of ๐‘“(๐‘ฅ) is given by the integral of ๐‘“(๐‘ฅ) multiplied by cosine(๐‘›๐œ‹๐‘ฅ/๐ฟ), where ๐‘› is an integer and ๐ฟ is the length of the interval of integration. In this case, ๐ฟ is infinity, so we can write the integral as:

๐น(๐‘›) = โˆซ[0,โˆž] ๐‘“(๐‘ฅ)cos(๐‘›๐œ‹๐‘ฅ/๐ฟ) ๐‘‘๐‘ฅ

Step 3: Substitute the given function ๐‘“(๐‘ฅ). Substituting ๐‘“(๐‘ฅ) = ๐‘ฅ ๐‘’โˆ’5๐‘ฅ into the integral, we have:

๐น(๐‘›) = โˆซ[0,โˆž] ๐‘ฅ ๐‘’โˆ’5๐‘ฅ cos(๐‘›๐œ‹๐‘ฅ/๐ฟ) ๐‘‘๐‘ฅ

Step 4: Simplify the integral. To simplify the integral, we can use integration by parts. Let's define ๐‘ข = ๐‘ฅ and ๐‘‘๐‘ฃ = ๐‘’โˆ’5๐‘ฅ cos(๐‘›๐œ‹๐‘ฅ/๐ฟ) ๐‘‘๐‘ฅ. Then, ๐‘‘๐‘ข = ๐‘‘๐‘ฅ and ๐‘ฃ = โˆ’(1/5)๐‘’โˆ’5๐‘ฅ sin(๐‘›๐œ‹๐‘ฅ/๐ฟ).

Using the integration by parts formula, the integral becomes:

๐น(๐‘›) = ๐‘ข๐‘ฃโˆฃ[0,โˆž] - โˆซ[0,โˆž] ๐‘ฃ๐‘‘๐‘ข

Simplifying further, we have:

๐น(๐‘›) = โˆ’(1/5)๐‘ฅ๐‘’โˆ’5๐‘ฅ sin(๐‘›๐œ‹๐‘ฅ/๐ฟ)โˆฃ[0,โˆž] + (1/5)โˆซ[0,โˆž] ๐‘’โˆ’5๐‘ฅ sin(๐‘›๐œ‹๐‘ฅ/๐ฟ) ๐‘‘๐‘ฅ

Step 5: Evaluate the integral. To evaluate the remaining integral, we can use the Fourier Sine Transform formula. The Fourier Sine Transform of ๐‘”(๐‘ฅ) = ๐‘’โˆ’๐‘Ž๐‘ฅ sin(๐‘๐‘ฅ) is given by:

๐บ(๐‘) = โˆซ[0,โˆž] ๐‘”(๐‘ฅ) sin(๐‘๐‘ฅ) ๐‘‘๐‘ฅ

In this case, ๐‘”(๐‘ฅ) = ๐‘’โˆ’5๐‘ฅ sin(๐‘›๐œ‹๐‘ฅ/๐ฟ), so we can write the integral as:

๐บ(๐‘›๐œ‹/๐ฟ) = โˆซ[0,โˆž] ๐‘’โˆ’5๐‘ฅ sin(๐‘›๐œ‹๐‘ฅ/๐ฟ) ๐‘‘๐‘ฅ

Using the Fourier Sine Transform formula, we find that ๐บ(๐‘›๐œ‹/๐ฟ) = (๐‘›๐œ‹/๐ฟ) / (๐‘›^2๐œ‹^2/๐ฟ^2 + 25).

Step 6: Substitute the result back into the previous integral. Substituting ๐บ(๐‘›๐œ‹/๐ฟ) = (๐‘›๐œ‹/๐ฟ) / (๐‘›^2๐œ‹^2/๐ฟ^2 + 25) into the previous integral, we have:

๐น(๐‘›) = โˆ’(1/5)๐‘ฅ๐‘’โˆ’5๐‘ฅ sin(๐‘›๐œ‹๐‘ฅ/๐ฟ)โˆฃ[0,โˆž] + (1/5)๐บ(๐‘›๐œ‹/๐ฟ)

Since the interval of integration is from 0 to infinity, the first term ๐‘ฅ๐‘’โˆ’5๐‘ฅ sin(๐‘›๐œ‹๐‘ฅ/๐ฟ) evaluated at infinity will be zero. Therefore, we are left with:

๐น(๐‘›) = (1/5)๐บ(๐‘›๐œ‹/๐ฟ)

Substituting ๐บ(๐‘›๐œ‹/๐ฟ) = (๐‘›๐œ‹/๐ฟ) / (๐‘›^2๐œ‹^2/๐ฟ^2 + 25), we finally get:

๐น(๐‘›) = (1/5) * (๐‘›๐œ‹/๐ฟ) / (๐‘›^2๐œ‹^2/๐ฟ^2 + 25)

This is the Fourier Cosine Transform of ๐‘“(๐‘ฅ) = ๐‘ฅ ๐‘’โˆ’5๐‘ฅ.

This problem has been solved

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