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Find the Fourier Cosine transform ๐น๐‘๐‘’-๐‘Ž๐‘ฅย of f(x) = ๐‘’-๐‘Ž๐‘ฅ where a>0Question 2Select one:-2๐œ‹๐‘Ž๐‘Ž2-๐‘ค22๐œ‹๐‘Ž๐‘Ž2+๐‘ค22๐œ‹-๐‘Ž๐‘Ž2+๐‘ค2-2๐œ‹๐‘Ž๐‘Ž2+๐‘ค2

Question

Find the Fourier Cosine transform ๐น๐‘๐‘’-๐‘Ž๐‘ฅย of f(x) = ๐‘’-๐‘Ž๐‘ฅ where a>0Question 2Select one:-2๐œ‹๐‘Ž๐‘Ž2-๐‘ค22๐œ‹๐‘Ž๐‘Ž2+๐‘ค22๐œ‹-๐‘Ž๐‘Ž2+๐‘ค2-2๐œ‹๐‘Ž๐‘Ž2+๐‘ค2

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Solution

The Fourier Cosine transform of a function f(x) is given by the formula:

F_c(w) = โˆš(2/ฯ€) โˆซ from 0 to โˆž [f(x) cos(wx) dx]

We want to find the Fourier Cosine transform of f(x) = e^-ax. Substituting this into the formula gives:

F_c(w) = โˆš(2/ฯ€) โˆซ from 0 to โˆž [e^-ax cos(wx) dx]

This is a standard integral that can be solved using integration by parts or by looking up in a table of integrals. The result is:

F_c(w) = โˆš(2/ฯ€) * [a / (a^2 + w^2)]

So, the Fourier Cosine transform of f(x) = e^-ax is F_c(w) = โˆš(2/ฯ€) * [a / (a^2 + w^2)].

Therefore, the correct answer is 2๐œ‹๐‘Ž/๐‘Ž^2+๐‘ค^2.

This problem has been solved

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Find the Fourier sine and cosine transform of f (t) = eโˆ’at, a > 0

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