n a manufacturing company, 5% of the items are defective. Assum-ing that successive items pass or fail independently of one another, calculatethe probability of each event
Question
n a manufacturing company, 5% of the items are defective. Assum-ing that successive items pass or fail independently of one another, calculatethe probability of each event
Solution
You didn't specify the events for which you want to calculate the probabilities. However, I can show you how to calculate the probability for a couple of common scenarios in this type of problem.
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Probability of the first item being defective: This is simply the percentage of defective items, which is 5% or 0.05.
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Probability of the first two items being defective: Since the problem states that the items pass or fail independently of one another, we can simply multiply the probabilities of each individual event. So, the probability of the first item being defective is 0.05, and the probability of the second item being defective is also 0.05. Therefore, the probability of both the first and second items being defective is 0.05 * 0.05 = 0.0025 or 0.25%.
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Probability of the first item being non-defective: This is simply 1 minus the probability of the item being defective, so 1 - 0.05 = 0.95 or 95%.
Please specify the events you're interested in if they're different from these examples.
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