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Find an equation of the circle that has center −1, 0 and passes through 3, 6.

Question

Find an equation of the circle that has center −1, 0 and passes through 3, 6.

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Solution

The equation of a circle is given by the formula (x - h)² + (y - k)² = r², where (h, k) is the center of the circle and r is the radius.

Step 1: Identify the center of the circle. In this case, the center (h, k) is given as (-1, 0).

Step 2: Find the radius of the circle. The radius is the distance between the center of the circle and any point on the circle. We are given the point (3, 6) on the circle. We can find the radius using the distance formula: r = sqrt[(x - h)² + (y - k)²]. Substituting the given values, we get r = sqrt[(3 - (-1))² + (6 - 0)²] = sqrt[(4)² + (6)²] = sqrt[16 + 36] = sqrt[52].

Step 3: Substitute the center and the radius into the equation of the circle. This gives us the equation of the circle as (x - (-1))² + (y - 0)² = sqrt[52]², or (x + 1)² + y² = 52.

This problem has been solved

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