A number when divided by a divisor left reminder 23. When twice of the number was divided by the same divisor, reminder was 11. what is the divisor?Options352512342

Let's denote the number as 'a' and the divisor as 'd'.

From the problem, we know that:

1. a = kd + 23 (where k is some integer)
2. 2a = ld + 11 (where l is some integer)

We can substitute the first equation into the second to get:

2(kd + 23) = ld + 11 2kd + 46 = ld + 11 2kd - ld = 11 - 46 (d)(2k - l) = -35

Since d is a divisor, it must be a positive integer. Therefore, the only possible value for d from the given options that can satisfy this equation is 35.

Let's denote the number as 'a' and the divisor as 'd'.

From the problem, we have two equations:

1. a = d*q1 + 23 (where q1 is the quotient of the first division)
2. 2a = d*q2 + 11 (where q2 is the quotient of the second division)

We can express a from the first equation and substitute it into the second equation:

2*(dq1 + 23) = dq2 + 11 2dq1 + 46 = dq2 + 11 2dq1 - dq2 = 11 - 46 d*(2*q1 - q2) = -35

Since d must be a positive integer, the only possible value from the options given that can divide -35 is 35. So, the divisor is 35.

Let's denote the number as 'a' and the divisor as 'd'.

From the problem, we have two equations:

1. a = d*q1 + 23 (where q1 is the quotient of the first division)
2. 2a = d*q2 + 11 (where q2 is the quotient of the second division)

We can express 'a' from the first equation and substitute it into the second equation:

a = dq1 + 23 2(dq1 + 23) = dq2 + 11 2dq1 + 46 = dq2 + 11 2dq1 - dq2 = 11 - 46 d*(2*q1 - q2) = -35

Since 'd' is a divisor, it must be a positive number. Also, 'q1' and 'q2' are quotients, they are also positive numbers. Therefore, the only way for the equation to hold true is when '2*q1 - q2' is a negative number.

Looking at the options, the only number that can divide -35 is 35. So, the divisor 'd' is 35.