Balance the following equation with the smallest whole number coefficients. Coefficients of one must be entered to received credit. NO2 (g) ⟶  N2O3 + O2 (g)

To balance the equation NO2 (g) ⟶ N2O3 (g) + O2 (g), follow these steps:

1. Identify the number of atoms for each element on both sides of the equation. In the unbalanced equation, there are 2 nitrogen atoms and 2 oxygen atoms on the left side, and 2 nitrogen atoms and 5 oxygen atoms on the right side.

2. Balance the nitrogen atoms first. In this case, the nitrogen atoms are already balanced with 2 on each side.

3. Next, balance the oxygen atoms. There are 2 oxygen atoms on the left and 5 on the right. To balance the oxygen atoms, you can put a coefficient of 2 in front of N2O3 on the right side of the equation. This gives you 6 oxygen atoms on the right side.

4. Now, you have 2 nitrogen atoms and 2 oxygen atoms on the left, and 4 nitrogen atoms and 6 oxygen atoms on the right. To balance the nitrogen atoms, put a coefficient of 2 in front of NO2 on the left side of the equation. This gives you 4 nitrogen atoms and 4 oxygen atoms on the left side.

5. Finally, to balance the oxygen atoms, put a coefficient of 1 in front of O2 on the right side of the equation. This gives you 4 nitrogen atoms and 6 oxygen atoms on both sides.

So, the balanced equation is: 2NO2 (g) ⟶ 2N2O3 (g) + 1O2 (g).