Balance the following equation: ___NH3 + ___O2 → ___NO2 + ___H2O The balanced equation shows that 1.00 mole of NH3 requires ___ mole(s) of O2Group of answer choices3.51.251.751.330.57
Question
Balance the following equation: ___NH3 + ___O2 → ___NO2 + ___H2O The balanced equation shows that 1.00 mole of NH3 requires ___ mole(s) of O2Group of answer choices3.51.251.751.330.57
Solution
To balance the chemical equation, we need to ensure that the number of atoms for each element is the same on both sides of the equation.
Let's start with the given equation: NH3 + O2 → NO2 + H2O
Step 1: Balance the Nitrogen (N) atoms first. There are 2 Nitrogen atoms on the right side (in NO2) and only 1 on the left side (in NH3). So, we put a coefficient of 2 in front of NH3:
2NH3 + O2 → NO2 + H2O
Step 2: Now, we have 2 Nitrogen atoms on both sides. Next, we balance the Hydrogen (H) atoms. There are 3 Hydrogen atoms in NH3 and 2 in H2O. Since we have a coefficient of 2 in front of NH3, we have 2*3=6 Hydrogen atoms on the left side. So, we put a coefficient of 3 in front of H2O to have 6 Hydrogen atoms on the right side as well:
2NH3 + O2 → NO2 + 3H2O
Step 3: Now, we have 2 Nitrogen atoms and 6 Hydrogen atoms on both sides. Finally, we balance the Oxygen (O) atoms. There are 2 Oxygen atoms in O2, 2 in NO2, and 31=3 in H2O. Since we have a coefficient of 2 in front of NO2, we have 22=4 Oxygen atoms on the right side. Adding the 3 Oxygen atoms from H2O, we have a total of 7 Oxygen atoms on the right side. So, we put a coefficient of 3.5 in front of O2 to have 7 Oxygen atoms on the left side as well:
2NH3 + 3.5O2 → 2NO2 + 3H2O
However, in chemical equations, we usually avoid fractional coefficients. So, we multiply all coefficients by 2 to get rid of the fraction:
4NH3 + 7O2 → 4NO2 + 6H2O
So, the balanced equation is: 4NH3 + 7O2 → 4NO2 + 6H2O
This means that 1.00 mole of NH3 requires 7/4 = 1.75 moles of O2. So, the answer is 1.75.
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