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Find the area of the region above the x-axis, included between the parabola ๐‘ฆ2=๐‘Ž๐‘ฅ and the circle ๐‘ฅ2+๐‘ฆ2=2๐‘Ž๐‘ฅ.

Question

Find the area of the region above the x-axis, included between the parabola ๐‘ฆ2=๐‘Ž๐‘ฅ and the circle ๐‘ฅ2+๐‘ฆ2=2๐‘Ž๐‘ฅ.

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Solution

To find the area of the region above the x-axis, included between the parabola ๐‘ฆยฒ=๐‘Ž๐‘ฅ and the circle ๐‘ฅยฒ+๐‘ฆยฒ=2๐‘Ž๐‘ฅ, we need to follow these steps:

  1. First, we need to find the points of intersection of the parabola and the circle. To do this, we substitute ๐‘ฆยฒ=๐‘Ž๐‘ฅ into the equation of the circle to get ๐‘ฅยฒ+๐‘Ž๐‘ฅ=2๐‘Ž๐‘ฅ. Simplifying this gives ๐‘ฅยฒ=๐‘Ž๐‘ฅ, so ๐‘ฅ=๐‘Ž or ๐‘ฅ=0.

  2. Now we need to find the y-coordinates of these points of intersection. Substituting ๐‘ฅ=๐‘Ž into ๐‘ฆยฒ=๐‘Ž๐‘ฅ gives ๐‘ฆยฒ=๐‘Žยฒ, so ๐‘ฆ=ยฑโˆš๐‘Žยฒ=ยฑ๐‘Ž. Since we are only interested in the region above the x-axis, we take ๐‘ฆ=๐‘Ž. Similarly, substituting ๐‘ฅ=0 into ๐‘ฆยฒ=๐‘Ž๐‘ฅ gives ๐‘ฆ=0.

  3. So the points of intersection are (0,0) and (๐‘Ž,๐‘Ž).

  4. Now we need to find the area of the region. To do this, we integrate the difference of the functions from 0 to ๐‘Ž. The function for the parabola is โˆš(๐‘Ž๐‘ฅ) and the function for the circle is โˆš(2๐‘Ž๐‘ฅ-๐‘ฅยฒ).

  5. So the area A is given by the integral from 0 to ๐‘Ž of [โˆš(2๐‘Ž๐‘ฅ-๐‘ฅยฒ) - โˆš(๐‘Ž๐‘ฅ)] dx.

  6. Evaluating this integral will give the area of the region.

This problem has been solved

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