Here is a step-by-step solution in Python: 1. First, initialize a variable `res` to 0. This will hold our reversed integer. 2. Check if the input integer `x` is negative. If it is, make it positive and remember that it was negative. 3. Start a while loop that continues as long as `x` is not 0. 4. In each iteration of the loop, get the last digit of `x` by taking `x mod 10` (in Python, this is `x % 10`). 5. Add this last digit to `res`, but since we're reversing the number, we need to first "shift" the current digits of `res` one place to the left. We do this by multiplying `res` by 10 before adding the last digit of `x`. 6. Remove the last digit from `x` by doing integer division by 10 (in Python, this is `x // 10`). 7. After the loop, `res` will hold the reversed integer. But we need to check if it's within the 32-bit signed integer range. If it's not, return 0. 8. Finally, if the original `x` was negative, return `-res`. Otherwise, return `res`. Here is the Python code for the above steps: ```python def reverse(x): res = 0 is_negative = x 2**31 - 1: return 0 return -res if is_negative else res ``` This function works by repeatedly "popping" the last digit off of `x` and "pushing" it onto `res`. The check for `res 2**31 - 1` ensures that `res` is within the 32-bit signed integer range.

Question

Here is a step-by-step solution in Python:

1. First, initialize a variable `res` to 0. This will hold our reversed integer.
2. Check if the input integer `x` is negative. If it is, make it positive and remember that it was negative.
3. Start a while loop that continues as long as `x` is not 0.
4. In each iteration of the loop, get the last digit of `x` by taking `x mod 10` (in Python, this is `x % 10`).
5. Add this last digit to `res`, but since we're reversing the number, we need to first "shift" the current digits of `res` one place to the left. We do this by multiplying `res` by 10 before adding the last digit of `x`.
6. Remove the last digit from `x` by doing integer division by 10 (in Python, this is `x // 10`).
7. After the loop, `res` will hold the reversed integer. But we need to check if it's within the 32-bit signed integer range. If it's not, return 0.
8. Finally, if the original `x` was negative, return `-res`. Otherwise, return `res`.

Here is the Python code for the above steps:

```python
def reverse(x):
    res = 0
    is_negative = x < 0
    x = abs(x)

while x != 0:
        digit = x % 10
        res = res * 10 + digit
        x //= 10

if res > 2**31 - 1:
        return 0

return -res if is_negative else res
```

This function works by repeatedly "popping" the last digit off of `x` and "pushing" it onto `res`. The check for `res > 2**31 - 1` ensures that `res` is within the 32-bit signed integer range.

Knowee AI · Accepted Answer

Here is a step-by-step solution in Python:

1. First, initialize a variable `res` to 0. This will hold our reversed integer.
2. Check if the input integer `x` is negative. If it is, make it positive and remember that it was negative.
3. Start a while loop that continues as long as `x` is not 0.
4. In each iteration of the loop, get the last digit of `x` by taking `x mod 10` (in Python, this is `x % 10`).
5. Add this last digit to `res`, but since we're reversing the number, we need to first "shift" the current digits of `res` one place to the left. We do this by multiplying `res` by 10 before adding the last digit of `x`.
6. Remove the last digit from `x` by doing integer division by 10 (in Python, this is `x // 10`).
7. After the loop, `res` will hold the reversed integer. But we need to check if it's within the 32-bit signed integer range. If it's not, return 0.
8. Finally, if the original `x` was negative, return `-res`. Otherwise, return `res`.

Here is the Python code for the above steps:

```python
def reverse(x):
    res = 0
    is_negative = x < 0
    x = abs(x)

while x != 0:
        digit = x % 10
        res = res * 10 + digit
        x //= 10

if res > 2**31 - 1:
        return 0

return -res if is_negative else res
```

This function works by repeatedly "popping" the last digit off of `x` and "pushing" it onto `res`. The check for `res > 2**31 - 1` ensures that `res` is within the 32-bit signed integer range.

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