The derivative of the function f is given by f'(x) = 3x + 4x^2. This is the derivative of the function f(x) = (3/2)x^2 + x^3 + C, where C is a constant.

To find the value of C, we can use the fact that the point (-1,0) lies on the graph of f. Substituting these values into the equation gives:

0 = (3/2)(-1)^2 + (-1)^3 + C
0 = 3/2 - 1 + C
0 = 1/2 + C

Solving for C gives C = -1/2.

So, the function f(x) = (3/2)x^2 + x^3 - 1/2.

Question

The derivative of the function f is given by f'(x) = 3x + 4x^2. This is the derivative of the function f(x) = (3/2)x^2 + x^3 + C, where C is a constant.

To find the value of C, we can use the fact that the point (-1,0) lies on the graph of f. Substituting these values into the equation gives:

0 = (3/2)(-1)^2 + (-1)^3 + C
0 = 3/2 - 1 + C
0 = 1/2 + C

Solving for C gives C = -1/2.

So, the function f(x) = (3/2)x^2 + x^3 - 1/2.

Knowee AI · Accepted Answer

The derivative of the function f is given by f'(x) = 3x + 4x^2. This is the derivative of the function f(x) = (3/2)x^2 + x^3 + C, where C is a constant.

To find the value of C, we can use the fact that the point (-1,0) lies on the graph of f. Substituting these values into the equation gives:

0 = (3/2)(-1)^2 + (-1)^3 + C
0 = 3/2 - 1 + C
0 = 1/2 + C

Solving for C gives C = -1/2.

So, the function f(x) = (3/2)x^2 + x^3 - 1/2.

The derivative of the function f is give by 𝑓′(𝑥)=3𝑥+4𝑥2. The point (-1,0) lie on the graph of f. Find an expression for f.What is the c value?f(x)= 𝑥2 +𝑥3 -

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