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Calculate the physical address for the 8086 microprocessor if CS = 17FBH and IP = ABCD H a)         2232B  Hb)         22B7D Hc)         22C8D Hd)         229CF  H

Question

Calculate the physical address for the 8086 microprocessor if CS = 17FBH and IP = ABCD H a)         2232B  Hb)         22B7D Hc)         22C8D Hd)         229CF  H

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Solution

The physical address for the 8086 microprocessor can be calculated using the formula:

Physical Address = CS * 10H + IP

where CS is the Code Segment register and IP is the Instruction Pointer register.

Let's calculate for each given CS and IP:

a) If CS = 17FBH and IP = 2232B H Physical Address = 17FBH * 10H + 2232B H = 17FB0H + 2232B H = 1A22DB H

b) If CS = 17FBH and IP = 22B7D H Physical Address = 17FBH * 10H + 22B7D H = 17FB0H + 22B7D H = 1A4C2D H

c) If CS = 17FBH and IP = 22C8D H Physical Address = 17FBH * 10H + 22C8D H = 17FB0H + 22C8D H = 1A4E3D H

d) If CS = 17FBH and IP = 229CF H Physical Address = 17FBH * 10H + 229CF H = 17FB0H + 229CF H = 1A457F H

Please note that the results are in hexadecimal (H).

This problem has been solved

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