Calculate the physical address for the 8086 microprocessor if CS = 17FBH and IP = ABCD H a) 2232B Hb) 22B7D Hc) 22C8D Hd) 229CF H
Question
Calculate the physical address for the 8086 microprocessor if CS = 17FBH and IP = ABCD H a) 2232B Hb) 22B7D Hc) 22C8D Hd) 229CF H
Solution
The physical address for the 8086 microprocessor can be calculated using the formula:
Physical Address = CS * 10H + IP
where CS is the Code Segment register and IP is the Instruction Pointer register.
Let's calculate for each given CS and IP:
a) If CS = 17FBH and IP = 2232B H Physical Address = 17FBH * 10H + 2232B H = 17FB0H + 2232B H = 1A22DB H
b) If CS = 17FBH and IP = 22B7D H Physical Address = 17FBH * 10H + 22B7D H = 17FB0H + 22B7D H = 1A4C2D H
c) If CS = 17FBH and IP = 22C8D H Physical Address = 17FBH * 10H + 22C8D H = 17FB0H + 22C8D H = 1A4E3D H
d) If CS = 17FBH and IP = 229CF H Physical Address = 17FBH * 10H + 229CF H = 17FB0H + 229CF H = 1A457F H
Please note that the results are in hexadecimal (H).
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