A person divides his total route of Journey into three equal parts and decides to travel them at the speeds of 40 kmph, 50 kmph and 20 kmph respectively. He completes his journey in 38 hours. Then the total distance travelled is
Question
A person divides his total route of Journey into three equal parts and decides to travel them at the speeds of 40 kmph, 50 kmph and 20 kmph respectively. He completes his journey in 38 hours. Then the total distance travelled is
Solution
To solve this problem, we need to use the formula for time, which is distance divided by speed.
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We know that the total time taken for the journey is 38 hours. This time is the sum of the times taken for each part of the journey.
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We also know that each part of the journey is the same distance. Let's call this distance 'd'.
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The time taken for the first part of the journey is d/40, for the second part it's d/50, and for the third part it's d/20.
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Therefore, we can set up the equation: d/40 + d/50 + d/20 = 38.
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To solve for 'd', we first need to find a common denominator for the fractions. The common denominator of 40, 50, and 20 is 200.
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So, the equation becomes: 5d/200 + 4d/200 + 10d/200 = 38.
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Simplifying this gives: 19d/200 = 38.
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Solving for 'd' gives: d = 38 * 200 / 19 = 400 km.
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Since the journey is divided into three equal parts, the total distance travelled is 3 * d = 3 * 400 = 1200 km.
So, the total distance travelled is 1200 km.
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