What is the change in specific enthalpy if water vapor at 80 bar and a quality of 0 is expanded to a saturated vapor at 100 bar?

To solve this problem, we need to use the steam tables to find the specific enthalpy (h) at the given states.

Step 1: Identify the initial state The initial state is water vapor at 80 bar with a quality of 0. This means it is saturated liquid.

Step 2: Find the specific enthalpy at the initial state Using the steam tables, look up the specific enthalpy of saturated liquid (hf) at 80 bar.

Step 3: Identify the final state The final state is saturated vapor at 100 bar.

Step 4: Find the specific enthalpy at the final state Using the steam tables, look up the specific enthalpy of saturated vapor (hg) at 100 bar.

Step 5: Calculate the change in specific enthalpy The change in specific enthalpy (Δh) is the difference between the specific enthalpy at the final state and the initial state.

Δh = hg (at 100 bar) - hf (at 80 bar)

Without the actual steam tables, I can't provide the numerical answer. But this is the process you would follow to find it.