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The heat of vaporization of water at 100°C is 40.66 kJ/mol. Calculate the quantity of heat that is released when 5.00 g of steam condenses to liquid water at 100°C. Hint: Convert 5.0 grams of water to moles (divide by the molar mass of H2O), multiply answer by the heat of vaporization.

Question

The heat of vaporization of water at 100°C is 40.66 kJ/mol. Calculate the quantity of heat that is released when 5.00 g of steam condenses to liquid water at 100°C. Hint: Convert 5.0 grams of water to moles (divide by the molar mass of H2O), multiply answer by the heat of vaporization.

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Solution

Sure, here are the steps to calculate the quantity of heat released:

  1. First, we need to convert the mass of water to moles. The molar mass of water (H2O) is approximately 18.015 g/mol. So, we divide the given mass of water by the molar mass of water:

    5.00 g / 18.015 g/mol = 0.277 moles

  2. Next, we multiply the number of moles by the heat of vaporization to find the total heat released. The heat of vaporization is the amount of heat required to convert one mole of a substance from a liquid state to a gaseous state at a constant temperature and pressure. In this case, it's given as 40.66 kJ/mol. So:

    0.277 moles * 40.66 kJ/mol = 11.27 kJ

So, the quantity of heat that is released when 5.00 g of steam condenses to liquid water at 100°C is approximately 11.27 kJ.

This problem has been solved

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