37, –33, –29, . . ., to 12 terms
Question
37, –33, –29, . . ., to 12 terms
Solution
This is an arithmetic sequence where each term increases by 4 from the previous term.
The first term (a) is 37 and the common difference (d) is -4.
The nth term of an arithmetic sequence can be found using the formula: a + (n - 1)d
To find the 12th term, we substitute the values into the formula:
37 + (12 - 1)(-4) = 37 + 11*(-4) = 37 - 44 = -7
So, the 12th term of the sequence is -7.
The sequence to 12 terms is: 37, -33, -29, -25, -21, -17, -13, -9, -5, -1, 3, -7.
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