What will be printed for the following code : if(x=0) cout<<”zero”; if(x>=0) cout<<”pos”; else cout<<”neg”;
Question
What will be printed for the following code : if(x=0) cout<<”zero”; if(x>=0) cout<<”pos”; else cout<<”neg”;
Solution
The code you've written will actually result in a compilation error. In most programming languages, the "=" operator is an assignment operator, not a comparison operator.
If you want to compare x to 0, you should use the "==" operator. So, the correct code should be:
if(x == 0)
cout<<"zero";
if(x >= 0)
cout<<"pos";
else
cout<<"neg";
Now, let's analyze this corrected code:
- If
xis equal to 0, it will print "zero" and then "pos" because 0 is also greater than or equal to 0. - If
xis greater than 0, it will only print "pos". - If
xis less than 0, it will print "neg".
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